You are one of the most talented programmers and like to
solve challenging problems. And my task is to make your life a bit complex by setting
some easy looking hard brain storming problems such that you can sharpen your
skills by practicing here. So, I wrote a code which shows a message like the
following line:
Greetings from LightOJ
After that the code will select a random problem for you
from my problems database based on your previously solved problems, your skills
and your weaknesses. But while I was coding for implementing this great idea, I
found that, all of my problems are scattered in 2 computers. So, I have
to merge them before running my code.
Now you are given the number of problems in each of the
computers, you have to find the total number of problems. You can safely assume
that no problem is stored in multiple computers. So, all the problems are
distinct.
Input
Input starts with an integer T (≤ 125),
denoting the number of test cases.
Each case starts with a line containing two integers a
and b. a denotes the number of problems in the first computer and
b denotes the number of problems in the second computer. You can safely
assume that a and b will be non-negative and not greater than 10.
Output
For each case, print the case number and the total number of
problems. See the samples for exact formatting.
Sample Input |
Output for Sample Input |
2
1
7
9
8
|
Case
1: 8
Case
2: 17
|
Problem Setter: Jane Alam Jan
Solution:
#include <stdio.h>
int main(){
static int T, t, A, B;
scanf("%d", &T);
for(t = 1; t <= T; t++){
scanf("%d%d", &A, &B);
printf("Case %d: %d\n", t, A+B);
}
return 0;
}
int main(){
static int T, t, A, B;
scanf("%d", &T);
for(t = 1; t <= T; t++){
scanf("%d%d", &A, &B);
printf("Case %d: %d\n", t, A+B);
}
return 0;
}
No comments:
Post a Comment